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New Delhi: Young Tamil Nadu cricketer Washington Sundar on Wednesday (December 13) became the seventh youngest cricketer to name an ODI debut for India. The bowling all-rounder was drafted in the playing XI in place of Kuldeep Yadav for the second ODI between India and Sri Lanka at the IS Bindra PCA Stadium in Mohali, Punjab. Earlier, Sundar replaced injured Kedar Jadhav in the ODI squad.
Sundar, who was also named in India’s T20I squad for Sri Lanka series, handed the India cap by head coach Ravi Shastri. The 18-year-old started his career as a batsman but made changes and became an off-spinner. He is known for his batting as well. Sundar was also part of India Under-19 World Cup squad last year and played for Rising Pune Supergiants in the Indian Premier League (IPL) season 10.
Sundar at 18 years and 69 days now becomes the seventh youngest player to represent India in ODIs and makes it to the list headed by Sachin Tendulkar.
Sachin Tendulkar – 16 years 238 days
Maninder Singh – 17 years 222 days
Harbhajan Singh – 17 years 288 days
Parthiv Patel – 17 years 301 days
Laxmi Ratan Shukla – 17 years 320 days
Chetan Sharma – 17 years 338 days
Washington Sundar – 18 years 69 days
— BCCI (@BCCI) December 13, 2017
The Tamil Nadu all-rounder ahead of the second ODI said he has worked harder on all aspects of his game to earn his place in the team.
“For any cricketer, playing for India is the ultimate dream. As an 18-year-old, I have got the opportunity to play for India and it is a great feeling. I trust a lot in my preparation and it has paid off,” Sundar was quoted as saying by IANS during the pre-match conference in Mohali.
“I went back, prepared a lot, trained a lot on aspects, where I needed to. It paid off. I started bowling more and spent extra time on my batting. And fitness also as you know it has become a very important aspect of this Indian team,” he added.