Unravelling JEE Main 2020 normalisation; know how NTA score and AIR is determined

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JEE Main will be held on January 9, 2020

The National Testing Agency (NTA) concluded Joint Entrance Examination Main (JEE Main) on January 9, 2020, in which around 11.18 lakh candidates appeared for the national level B.E / B.Tech, B.Arch, and B.Plan paper. They are now awaiting the JEE Main 2020 answer key to release.

Through the answer key, candidates can match answers and predict the raw score. However, the result of JEE Main is determined on the basis of normalised scores and not the raw scores.

Let's understand how the normalised score of JEE Main, called the NTA score, is determined.

What is normalisation?

Normalisation is a method that is used for bringing values on different scales to a common scale. In case of the entrance examination, it is generally used in the online mode where a huge number of candidates appear in different slots.

These candidates get a different set of questions, with varied difficulty levels. So, the conducting body uses the normalisation technique to adjust the level of difficulty in the slot.

How NTA calculates percentile score using the normalisation method

The JEE Main 2020 was conducted in a window of four days, with two sessions held daily. In the January exam result, the NTA score of candidates will be mentioned. The all-India rank will be announced after the April examination. The NTA score is the normalised score and indicates the number of candidates who have scored equal to or less than the candidate.

The formula used to calculate the percentile score is:

100 x Number of candidates that appeared in the ‘session’ with raw score equal to or less than the candidate / Total number of candidates appeared in the ‘session’.

Using this formula, the overall percentile score of the candidates are determined. NTA also determines subject-wise percentile of the candidates.

Here, the highest percentile score in each session shall be 100. Hence, if the overall percentile score of a candidate is 45, then there are 55 candidates who score more than the candidate.

What is the use of percentile score and how is AIR determined?

The All India Rank of the candidates is determined on the basis of the percentile score. The better the score of the candidates, the higher is AIR. NTA announces JEE Main AIR after the April examination. Candidates who appear for any of the JEE exams get ranked on the basis of overall percentile. However, candidates who appear for both the papers get ranked on the basis of their better overall percentile score out of both attempts.

What is done in case of a tie?

At times, multiple candidates get the same percentile score. In this case, NTA uses the tie-breaking method to allocate the percentile score and rank. Under this method, NTA checks which candidate has secured a higher percentile score in Mathematics. The candidate with higher marks gets the rank.

However, if this does not work and the percentile score clashes, then higher percentile marks in Physics, followed by Chemistry scores are considered. Again, the candidates with higher marks get a higher rank. If the tie persists even after this, then the older candidate is allocated a better AIR.